Question
nment E MY INSTRUCTOR FULL SCREEN VERSION | | BACK Question 6 e parallel axis theorem provides a useful way to calculate the moment of inertial about an arbitrary a is. The theorem states that 1 1 + Mh2 where I m is the moment of inertia of the object relative to an axis that passes through the center of mass and is parallel to the axis of interest, M is the total mass of the object, and h is the perpendicular distance between the two axes. Use this theorem and information to determine the moment of inertia (kg-m2) of a solid cylinder of mass M = 8.50 kg and radius R 5.00 m relative to an axis that lies on the surface of the cylinder and is perpendicular to the circular ends. Number Units the tolerance is +/-2% Click if you would like to Show Work for this question: Open Show Work LINK TO TEXT Question Attempts: 0 of 5 used SAVE FOR LATER Copyright © 2000-2015 by John Wiley & Sons, Inc. or related companies. All rots reserved
Explanation / Answer
Icm = MR^2 /2 = 8.50 x 5^2 /2 = 106.25 kg.m^2
I = 106.25 + 8.50 x 5^2 = 318.75 kg.m^2
