A 12.00-V battery is connected through a switch to two identical resistors and a

Question

A 12.00-V battery is connected through a switch to two identical resistors and an ideal inductor, as shown in the figure. Each of the resistors has a resistance of 146.0 ?, and the inductor has an inductance of 5.00 H. The switch is initially open.
(For each of the following parts enter your answers in units of A, separated by a comma.
Example: if you think that the answer is i1 = 1 A, and i2 = 3 A, then enter 1,3).

a) Immediately after the switch is closed, what is the current in resistor R1and in resistor R2?

b) At 50 ms after the switch is closed, what is the current in resistor R1 and in resistor R2?

c) At 500 ms after the switch is closed, what is the current in resistor R1 and in resistor R2?

A 12.00-V battery is connected through a switch to two identical resistors and an ideal inductor, as shown in the figure. Each of the resistors has a resistance of 146.0 ?, and the inductor has an inductance of 5.00 H. The switch is initially open. (For each of the following parts enter your answers in units of A, separated by a comma. Example: if you think that the answer is i1 = 1 A, and i2 = 3 A, then enter 1,3). a) Immediately after the switch is closed, what is the current in resistor R1and in resistor R2? b) At 50 ms after the switch is closed, what is the current in resistor R1 and in resistor R2? c) At 500 ms after the switch is closed, what is the current in resistor R1 and in resistor R2?

Explanation / Answer

part A:

immediately after the switch is closed,

Currnent I1 = V/R = 12/146 = 0.082 A

----------------------

use I = Io e^-Rt/L

I = 0.082* e^(-146 * 0.05/(5)

I = 0.019 A

-------------------------------
Use again I = Io e^-Rt/L

I = 0.082 * e^(-146* 0.5)/5

I = 0.00413 uA

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.