Two circuits contain an emf produced by a moving metal rod, like that shown in t
ID: 1262301 • Letter: T
Question
Two circuits contain an emf produced by a moving metal rod, like that shown in the drawing. The speed of the rod is the same in each circuit, but the bulb in circuit 1 has one-half the resistance of the bulb in circuit 2. The circuits are otherwise identical. The resistance of the light bulb in circuit 1 is 43 ?, and that in circuit 2 is 86 ?. Determine (a) the ratio ?1/?2 of the emfs and (b) the ratioI1/I2 of the currents in the circuits. (c) If the speed of the rod in circuit 1 were twice that in circuit 2, what would be the ratio P1/P2 of the powers in the circuits?
Two circuits contain an emf produced by a moving metal rod, like that shown in the drawing. The speed of the rod is the same in each circuit, but the bulb in circuit 1 has one-half the resistance of the bulb in circuit 2. The circuits are otherwise identical. The resistance of the light bulb in circuit 1 is 43 ?, and that in circuit 2 is 86 ?. Determine (a) the ratio ?1/?2 of the emfs and (b) the ratioI1/I2 of the currents in the circuits. (c) If the speed of the rod in circuit 1 were twice that in circuit 2, what would be the ratio P1/P2 of the powers in the circuits?Explanation / Answer
(a) In the two circuits B, v and L are same. Therefore, the value of the ratio ?1 / ?2 is,
?1 / ?2 = BvL /BvL = 1
(b) The value of the ratio, I1 / I2 is, I1 / I2 = R2 / R1 = 86 / 43= 2
(c) We know that P = I2R , then the value of the ratio, P1 / P2 is, P1 / P2 = 4(R2 / R1)= 8
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