Two circuits contain an emf produced by a moving metal rod, like that shown in t
ID: 1286400 • Letter: T
Question
Two circuits contain an emf produced by a moving metal rod, like that shown in the drawing. The speed of the rod is the same in each circuit, but the bulb in circuit 1 has one-half the resistance of the bulb in circuit 2. The circuits are otherwise identical. The resistance of the light bulb in circuit 1 is 423 ohms, and that in circuit 2 is 846 ohms
(b) Determine the ratio I1/I2 of the currents in the circuits.
(c) If the speed of the rod in circuit 1 were twice that in circuit 2, what would be the ratio P1/P2 of the powers in the circuits?
Two circuits contain an emf produced by a moving metal rod, like that shown in the drawing. The speed of the rod is the same in each circuit, but the bulb in circuit 1 has one-half the resistance of the bulb in circuit 2. The circuits are otherwise identical. The resistance of the light bulb in circuit 1 is 423 ohms, and that in circuit 2 is 846 ohms (a) Determine the ratio E 2 of the emfs (b) Determine the ratio I1/I2 of the currents in the circuits. (c) If the speed of the rod in circuit 1 were twice that in circuit 2, what would be the ratio P1/P2 of the powers in the circuits? E 1Explanation / Answer
a)
Induced emf
E=BLV
Since B,L and V are same
E1/E2=1
b)
I=E/R
I1/I2=R2/R1=846/423 =2
c)
since power
P=E2/R
P1/P2=(R2/R1)=2
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