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Two circuits contain an emf produced by a moving metal rod, like that shown in t

ID: 1286400 • Letter: T

Question

Two circuits contain an emf produced by a moving metal rod, like that shown in the drawing. The speed of the rod is the same in each circuit, but the bulb in circuit 1 has one-half the resistance of the bulb in circuit 2. The circuits are otherwise identical. The resistance of the light bulb in circuit 1 is 423 ohms, and that in circuit 2 is 846 ohms

(b) Determine the ratio I1/I2 of the currents in the circuits.

(c) If the speed of the rod in circuit 1 were twice that in circuit 2, what would be the ratio P1/P2 of the powers in the circuits?

Two circuits contain an emf produced by a moving metal rod, like that shown in the drawing. The speed of the rod is the same in each circuit, but the bulb in circuit 1 has one-half the resistance of the bulb in circuit 2. The circuits are otherwise identical. The resistance of the light bulb in circuit 1 is 423 ohms, and that in circuit 2 is 846 ohms (a) Determine the ratio E 2 of the emfs (b) Determine the ratio I1/I2 of the currents in the circuits. (c) If the speed of the rod in circuit 1 were twice that in circuit 2, what would be the ratio P1/P2 of the powers in the circuits? E 1

Explanation / Answer

a)

Induced emf

E=BLV

Since B,L and V are same

E1/E2=1

b)

I=E/R

I1/I2=R2/R1=846/423 =2

c)

since power

P=E2/R

P1/P2=(R2/R1)=2

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