A cannonball is shot from a cannon, at an initial height of 1.1 meters. At the p

Question

A cannonball is shot from a cannon, at an initial height of 1.1 meters. At the peak of the trojectory, it strikes a smiley face picture, located 4.1 meters to the right, (define the i-axis to the right, and define the j-axis as up) HINT: In order to solve this, you have to understand what At the peak of the trajectory means. It means at the maximum height of the cannonball. The initial speed of the cannonball is 9.0 m/s, and it is shot at an angle of 40 degree. (a) Calculate the initial velocity (Remember: Velocity is a vector! You need to use i-j notation) (b) Calculate the velocity at the peak of the trajectory, so just before it strikes (he picture. (Again, use i-j notation) (c) Calculate the time in the air before it strikes the picture. Bonus: You shoot a second cannonball, but it misses the picture. so it Lands on the ground. How long is it in the air?

Explanation / Answer

Here the solution for this problem:

a) V=9cos40

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