A cannonball is shot at a speed of 108 km/h making an angle of 53 with the horiz

Question

A cannonball is shot at a speed of 108km/h  making an angle of53 with the horizontal. The cannon ball flies overtwo buildings that are 18 m tall. The first building is 24m away from the origin and the second building is44.14 m away. a) How long does the ball take to fly over the firstbuilding? b) What is the clearance if the ball when it flies over thefirst building? c) If the ball reached a maximum height over the secondbuilding, by how much it clears that building? (Hint: find themaximum height) d) If the cannonball lands on the ground, find the time thatit takes to complete the motion.
a) How long does the ball take to fly over the firstbuilding? b) What is the clearance if the ball when it flies over thefirst building? c) If the ball reached a maximum height over the secondbuilding, by how much it clears that building? (Hint: find themaximum height) d) If the cannonball lands on the ground, find the time thatit takes to complete the motion.

Explanation / Answer

U = 108 km/h = 30 m/s ux = u. cos = 18.05 m/s uy = u. sin = 23.96 m/s (a) x1 = ux.t1        t1 = x1/ux = 24/18.05=1.329 s (b) y1 = uy.t1 - 4.9 t1^2            =23.19 m Clearance y1 = 23.19 - 18 = 5.19 m (c) ymax (for vy = 0) = u^2/2g = 29.29 m Clearance, y2 = 29.29 -18 = 11.29 m (d) For the complete flight, y = 0          T = 2*uy/g =4.89 s If you need any more expln let meknow.       

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