A rectangular conducting loop on a frictionless horizontal table initially lies

Question

A rectangular conducting loop on a frictionless horizontal table initially lies entirely in a uniform magnetic of magnitude 0.25 T with its right edge at the edge of the field (Figure 1(a)). The loop is pulled to the right for 1.5 s until the entire loop is out of the field (Figure 1(b)). During that time, the magnetic force on the loop is 7.5 x 10^-4 N to the left. (a) Initial position of loop (b) Final position of loop Figure 1: Loop on horizontal table viewed from above. a) Determine the rate of change of flux, delta phi/delta t, through the loop during the time it is pulled out of the field.

Explanation / Answer

Flux = B.A =0.25*0.05*0.02 = 2.5*10^-4

Flux/time = 2.5*10^-4/1.5 = 1.67 * 10^-4 Volts

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