explanation & answers, please Calculate the wavelength of light in vacuum that h

Question

explanation & answers, please Calculate the wavelength of light in vacuum that has a frequency of 9.8 x 10 Hz. What is the wavelength in ethyl alcohol? (The index of refraction of ethyl alcohol is 1.361.) Calculate the energy of one photon of such light in vacuum. Express the answer in electron volts. What is the properties of and effect on the energy of the photon when it enters the ethyl alcohol? (Select all that apply.) the energy is not proportional to the frequency the energy is proportional to the frequency the energy goes down the energy goes up the energy is inversely proportional to the frequency the energy does not change

Explanation / Answer

a)wavelength = c/f = (3*10^8 )/ (9.8*10^12)= 0.306 * 10^-4 m =30.6 micrometres

b)wavelength in ethyl alcohol= 30.6*1.361=41.646 micrometres

c)energy=

hc/lambda

= (6.625 * 10^-34 * 3 * 10^8)/30.6 * 10^-6

=0.6495 * 10^-20 joules = (0.6495 * 10^-20)/(1.6*10^-19)=0.406 * 10^-1=0.0406 eV

d) the energy is proprotional to frequency

the energy does not change

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