Find the current in each resistor. Find the rate at which energy is being delive

Question

Find the current in each resistor.

Find the rate at which energy is being delivered to the 6.0? resistor.

2)Two parallel plates, 6.75cm on a side, are separated by 3.32 mm.Determine their capacitance if the volume from one plate to midplane is filled with a material of dielectric constant 2.55 and the rest is filled with a different material of dielectric constant 4.10. If these plates are connected to a 12-V battery, what is the electric field strength in the dielectric region with ?1= 2.55 ?What is the electric field strength in the dielectric region with?2= 4.10 ?

Explanation / Answer

1.

since R1 and R2 are in parallel

1/R12=1/R1+1/R2=1/4 +1/6

R12=2.4 ohms

Applying KVL in the Loop

-6+I*R3+I*R12-12+I*R5+I*R4=0

-18+I*(2+2.4+2+8)=0

I=18/14.4 =1.25 A

So Current each resistor is

I1=I*(R2/R1+R2) =1.25*(6/6+4) =0.75 A

I2=I*(R1/R1+R2) =1.25*(4/6+4) =0.50 A

I3=1.25 A

I4=1.25 A

I5=1.25 A

b)

Power in 6ohms resistor is

P6=I22R2 =0.52*6

P6=1.5 Watts

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