An air-track glider with mass .100kg is attached to the end of a horizontal air
ID: 1271435 • Letter: A
Question
An air-track glider with mass .100kg is attached to the end of a horizontal air track by a spring with force constant 20.0 N/m. Initially the spring is unstreched and the glider is moving at 1.50 m/s to the right. With the air track turned off, the coefficient of kinetic friction is ?k=0.47. Part A How large would the coefficient of static friction ?s have to be to keep the glider from springing back to the left when it stops instantaneously? Part B If the coefficient of static friction between the glider and the track is ?s = 0.80, what is the maximum initial speed v1 that the glider can be given and still remain at rest after it stops instantaneously? PLEASE HELP! Last time I asked this question on here it was wrong and I'm really struggling. An air-track glider with mass .100kg is attached to the end of a horizontal air track by a spring with force constant 20.0 N/m. Initially the spring is unstreched and the glider is moving at 1.50 m/s to the right. With the air track turned off, the coefficient of kinetic friction is ?k=0.47. Part A How large would the coefficient of static friction ?s have to be to keep the glider from springing back to the left when it stops instantaneously? Part B If the coefficient of static friction between the glider and the track is ?s = 0.80, what is the maximum initial speed v1 that the glider can be given and still remain at rest after it stops instantaneously? PLEASE HELP! Last time I asked this question on here it was wrong and I'm really struggling. An air-track glider with mass .100kg is attached to the end of a horizontal air track by a spring with force constant 20.0 N/m. Initially the spring is unstreched and the glider is moving at 1.50 m/s to the right. With the air track turned off, the coefficient of kinetic friction is ?k=0.47. An air-track glider with mass .100kg is attached to the end of a horizontal air track by a spring with force constant 20.0 N/m. Initially the spring is unstreched and the glider is moving at 1.50 m/s to the right. With the air track turned off, the coefficient of kinetic friction is ?k=0.47. An air-track glider with mass .100kg is attached to the end of a horizontal air track by a spring with force constant 20.0 N/m. Initially the spring is unstreched and the glider is moving at 1.50 m/s to the right. With the air track turned off, the coefficient of kinetic friction is ?k=0.47. Part A How large would the coefficient of static friction ?s have to be to keep the glider from springing back to the left when it stops instantaneously? Part B If the coefficient of static friction between the glider and the track is ?s = 0.80, what is the maximum initial speed v1 that the glider can be given and still remain at rest after it stops instantaneously? PLEASE HELP! Last time I asked this question on here it was wrong and I'm really struggling. Part A How large would the coefficient of static friction ?s have to be to keep the glider from springing back to the left when it stops instantaneously? Part B If the coefficient of static friction between the glider and the track is ?s = 0.80, what is the maximum initial speed v1 that the glider can be given and still remain at rest after it stops instantaneously? PLEASE HELP! Last time I asked this question on here it was wrong and I'm really struggling. Part A How large would the coefficient of static friction ?s have to be to keep the glider from springing back to the left when it stops instantaneously? Part B If the coefficient of static friction between the glider and the track is ?s = 0.80, what is the maximum initial speed v1 that the glider can be given and still remain at rest after it stops instantaneously? PLEASE HELP! Last time I asked this question on here it was wrong and I'm really struggling. Part B If the coefficient of static friction between the glider and the track is ?s = 0.80, what is the maximum initial speed v1 that the glider can be given and still remain at rest after it stops instantaneously? PLEASE HELP! Last time I asked this question on here it was wrong and I'm really struggling.Explanation / Answer
Energy = 1/2 m v^2 = 0.5 . 0.1 . 1.5^2 = 0.1125 J
0.1125 = 0.5 . 20 . x^2
x = 0.106 m
F = kx = 2.12 N
This must be the friction force 2.12 =
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