The potential in a region between x = 0 and x = 6.00 m is V = a + bx, where a =

Question

The potential in a region between x = 0 and x = 6.00 m is V = a + bx, where a = 18.6 V and b = -3.50 V/m.

(a) Determine the potential at x = 0.
__________________V

Determine the potential at x = 3.00 m.

__________________V

Determine the potential at x = 6.00 m.

__________________V

(b) Determine the magnitude and direction of the electric field at x = 0.

magnitude : ____________________ V/m

Determine the magnitude and direction of the electric field at x = 3.00 m.

magnitude : ____________________ V/m

Determine the magnitude and direction of the electric field at x = 6.00 m.

magnitude : ____________________ V/m

Explanation / Answer

a)

at x=0

V(0)=a =18.6 Volts

at x=3

V(3)=18.6+(-3.5)*3 =8.1 Volts

at x=6 m

V(6)=18.6+(-3.5)*6=-2.4 Volts

b)

Electric field

E=-dV/dx =b

E=3.5 V/m

at any point 0<=x<=6 ,so

at x=0=>E=3.5 V/m

at x=3=>E=3.5 V/m

atx=6=>E=3.5 V/m

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