A planet of mass m = 1.55 x 10 24 kg is orbiting in a circular path a star of ma

Question

A planet of mass m = 1.55 x 1024 kg is orbiting in a circular path a star of mass M = 9.75 x 1029 kg. The radius of the orbit is R = 4.65 x 107 km. What is the orbital period (in earth days) of the planet? Where G = 6.67 10-11 Nm2/kg2 and 1 day = 8.54 104 s.

What am I doing wrong?

A planet of mass m = 1.55 x 1024 kg is orbiting in a circular path a star of mass M = 9.75 x 1029 kg. The radius of the orbit is R = 4.65 x 107 km. What is the orbital period (in earth days) of the planet? Where G = 6.67 1/2 10-11 N 1/2 m2/kg2 and 1 day = 8.54 1/2 104 s. I used the formula T^2/r^3 = 4pi^2/GM and got T = 247 s = 0.0289 days, but the online homework system says thats the wrong answer. what am I doing wrong?

Explanation / Answer

T = 2*pi sqrt(r^3 / GM)
R=4.65*10^7km= 4.65*10^10metre

M=mass of star=9.75 x 1029 kg

T=7686902.828 sec or 90.01 days make sure u converted the radius in metres and took mass of star

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