A blue car with mass m c = 455 kg is moving east with a speed of v c = 19 m/s an

Question

A blue car with mass mc = 455 kg is moving east with a speed of vc = 19 m/s and collides with a purple truck with mass mt = 1237 kg that is moving south with a speed of vt = 10 m/s . The two collide and lock together after the collision.

1)

What is the magnitude of the initial momentum of the car?

kg-m/s

2)

What is the magnitude of the initial momentum of the truck?

kg-m/s

3)

What is the angle that the car-truck combination travel after the collision? (give your answer as an angle South of East)

cartruckcollisionnew A blue car with mass mc = 455 kg is moving east with a speed of vc = 19 m/s and collides with a purple truck with mass mt = 1237 kg that is moving south with a speed of vt = 10 m/s . The two collide and lock together after the collision. 1) What is the magnitude of the initial momentum of the car? kg-m/s 2) What is the magnitude of the initial momentum of the truck? kg-m/s 3) What is the angle that the car-truck combination travel after the collision? (give your answer as an angle South of East) ? 4) What is the magnitude of the momentum of the car-truck combination immediately after the collision? kg-m/s 5) What is the speed of the car-truck combination immediately after the collision? m/s 6) Compare the initial and final kinetic energy of the total system before and after the collision: KEi = KEf KEi > KEf KEi

Explanation / Answer

initial momentum of a car=mc*vc

initial momentum of a truck=mt*vt

angle will be more towards south

momentum will be same as initial immediately after colllison

speed immediately after collision v=(mcvc+mtvt)/(mc+mt)

KEi=KEf

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