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When electrons bombard a molybdenum target, they produce both continuous and cha

ID: 1282349 • Letter: W

Question

When electrons bombard a molybdenum target, they produce both continuous and characteristic x rays as shown in the figure. In that figure the kinetic energy of the incident electrons is 35.0 keV. If the accelerating potential is increased to 66.3 keV, (a) what are the values of Lamdamin, (b) do the wavelengths of the Ka and KB lines increase, decrease, or remain the same?

When electrons bombard a molybdenum target, they produce both continuous and characteristic x rays as shown in the figure. In that figure the kinetic energy of the incident electrons is 35.0 keV. If the accelerating potential is increased to 66.3 keV, (a) what are the values of Lamdamin, (b) do the wavelengths of the Ka and KB lines increase, decrease, or remain the same?

Explanation / Answer

1240/(lambda) = E where

So here you put the new accelerating potential of 63.5.

Or 1240/63.5 = 19.527 pm

As for the second part, KA and KB remain the same

The wavelengths that we get are because of the fact that on getting the minimum required threshold energy, molybdenum will eject sub atomic particles. Now this ejection causes the highly energised particles to emit energy. This energy has a particular wavelength. The particles will eject as soon as they get the minimum required energy. their ejection does not depend on the incident energy. And since the wavelength is fixed for a particular energy level KA and KB remain the same

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