(a)Note: We suggest you use ray diagrams to qualitatively understand these quest

Question

(a)Note: We suggest you use ray diagrams to qualitatively understand these questions. A candle 8.70 cm high is placed in front of a thin converging lens of focal length 31.5 cm. What is the image distance i when the object is placed 92.0 cm in front of the same lens?

(b) What is the size of the image? (Note: an inverted image will have a `negative' size.)

(c) Is the image real(R) or virtual(V); upright(U) or inverted(I); larger(L) or smaller(S) or unchanged(UC); in front of the lens(F) or behind the lens(B)? Answer these questions in the order that they are posed. (for example, if the image is real, inverted, larger and behind the lens then enter `RILB'.)

(d) The object is now moved to 41.5 cm in front of the lens, what is the new image distance i?

(e) What is the new size of the image?

(f) Is the new image real(R) or virtual(V); upright(U) or inverted(I); larger(L) or smaller(S) or unchanged(UC); in front of the lens(F) or behind the lens(B)? Answer these questions in the order that they are posed. (for example, if the image is real, inverted, larger and behind the lens then enter `RILB'.)

(g) The object is now moved to 27.5 cm in front of the lens, what is the new image distance i?

(h) What is the new size of the image?

(i) Is the new image real(R) or virtual(V); upright(U) or inverted(I); larger(L) or smaller(S) or unchanged(UC); in front of the lens(F) or behind the lens(B)? Answer these questions in the order that they are posed. (for example, if the image is real, inverted, larger and behind the lens then enter 'RILB'.)

(j) The object is now moved to 6.0 cm in front of the lens, what is the new image distance i?

(k) What is the new size of the image?

(l) Is the new image real(R) or virtual(V); upright(U) or inverted(I); larger(L) or smaller(S) or unchanged(UC); In front of the lens(F) or behind the lens(B)? Answer these questions in the order that they are posed. (for example, if the image is real, inverted, larger and behind the lens then enter 'RILB'.)

Explanation / Answer

1/o + 1/i = 1/f

i = of/(o-f)

hi/ho = i/O========> hi = (ho*i)/o

1) i = (108.5*35)/(108.5-35) = 51.6 cm

2) hi = (7*51.6)/108.5 = 3.29 cm

3) RILB

4) i = (44.5*35)/(44.5-35) = 163.94 cm

hi = (7*163.94)/44.5 = 25.78 cm

5) RILB

6) i = (22*35)/(22-35) = -59.23 cm

hi = (7*59.23)/22 = 18.84 cm

7) VULF

8) i = (10.5*35)/(10.5-35) = -15 cm

hi = (7*15)/10.5 = 10 cm

9) VULF

Related Questions

Navigate

• Browse (All)
• Browse #
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.