a 50g mass, M1 moves with a speed v=4.2 m/s in a circular path of radius R=45 cm

Question

a 50g mass, M1 moves with a speed v=4.2 m/s in a circular path of radius R=45 cm on a frictionless horizontal table. it is attatched to a string that passes through a frictionless hole in the centrer of the table. a second mass M2, is attached to the other end of the string.

due to the circular motion of M1, M2 does not fall. Find the value for mass M2

a 50g mass, M1 moves with a speed v=4.2 m/s in a circular path of radius R=45 cm on a frictionless horizontal table. it is attatched to a string that passes through a frictionless hole in the centrer of the table. a second mass M2, is attached to the other end of the string. due to the circular motion of M1, M2 does not fall. Find the value for mass M2

Explanation / Answer

Force equation on M1

T = M1V^2/R

Force equation on M2

T = M2 * g

From two equations ( since T is same)

M1V^2/R = M2*g

M2 = 0.19979kg

M2=199.79 gm

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