1. What two conditions must be met for a rigid object to be in static equilibriu
ID: 1286035 • Letter: 1
Question
1. What two conditions must be met for a rigid object to be in static equilibrium? 2. What is meant by the center of mass of an object? Do you think the center of mass of the torque bar used in the revised Experiment 11 is at the center of the bar? If not, to which end is it the closest, L or R and why? (Refer to the figure in the Experiment 11 to answer this question.) 3. For the torque bar on the figure bellow, write symbolic equations for static equilibrium conditions, choose point A for pivot. Make sure to use the right coordinate system. What additional complication arises if you choose pivot point at the left end of the torque bar? 4. For question 3 state whether the torque around points A, D, and the center of mass is positive or negative. Explain your answer.Explanation / Answer
1. the two conditions are-
(i)the sum of all forces should be zero.
(ii) the moment should be zero on rigid object.
2.the center of mass of a distribution of mass in space is the unique point where the weighted relative
position of the distributed mass sums to zero. The distribution of mass is balanced around the center of
mass and the average of the weighted position coordinates of the distributed mass defines its coordinates.
No.COM is nt at center.it is right because the rod is tilted with angle theta.
3.for force balance
T1 cos(theta_b)=T_2 cos(theta_d)
T_1 sin(theta_b)+T_2 sin(theta_b)=m*g
for torque balance
T_2*AD=mg*x
x=COM
The additional complication will be that we have to balance both force and moment.
4. Torque around point A and D is +ve and around COM is -ve.using Right hand thumb rule,torque point inward is negative while pointing outward it is +ve.
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