A batter hits a 0.140-kg baseball that was approaching him at 30 m/s and, as a r

Question

A batter hits a 0.140-kg baseball that was approaching him at 30 m/s and, as a result, the ball leaves the bat at 40 m/s in the reverse of its original direction. The ball remains in contact with the bat for 2.0 ms. What is the magnitude of the average force exerted by the bat on the ball?
A batter hits a 0.140-kg baseball that was approaching him at 30 m/s and, as a result, the ball leaves the bat at 40 m/s in the reverse of its original direction. The ball remains in contact with the bat for 2.0 ms. What is the magnitude of the average force exerted by the bat on the ball?

Explanation / Answer

imuplse = chnage in momentum

Favg*t = m*(v2-v1)

Favg = m*(v2-v1)/t

= 0.14*(40 - (-30))/2*10^-3

= 4900 N

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