A small block of mass m = 1.4 kg slides, without friction, along the loop-the-lo

Question

A small block of mass m = 1.4 kg slides, without friction, along the loop-the-loop track shown. the block starts from the point P a distance h = 52.0 m above the bottom of the loop of radius R = 16.0 m. What is the kinetic energy of the mass at the point A on the loop? What is the downward acceleration of the mass at the point A of the loop?

A small block of mass m = 1.4 kg slides, without friction, along the loop-the-loop track shown. the block starts from the point P a distance h = 52.0 m above the bottom of the loop of radius R = 16.0 m. What is the kinetic energy of the mass at the point A on the loop? What is the downward acceleration of the mass at the point A of the loop?

Explanation / Answer

kinetic energy= change in potential energy

= mgH- mg(2R)

= 1.4*10*(52-32)= 280J

Velocity at pointA,

280= 1/2* 1.4* v2

V= 20m/s

Downward acc= V2/R

= 400/16= 25 m/s2

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