A laser beam is incident on two slits seperated by .4mm. The interference patter

Question

A laser beam is incident on two slits seperated by .4mm. The interference pattern is formed on a screen 1 metrr from the slits and the first bright fringe is found to be .120cm to the right of tr central maximum. What is the wavelength of the light?
A laser beam is incident on two slits seperated by .4mm. The interference pattern is formed on a screen 1 metrr from the slits and the first bright fringe is found to be .120cm to the right of tr central maximum. What is the wavelength of the light?
What is the wavelength of the light?

Explanation / Answer

Here fringe width 0.12cm=0.0012

D=1 m

d=0.4 mm = 0.0004 m

Lambda = width X d/D

=0.0012x 0.0.0004 /1

=480 nm

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