A uniform disk with mass 37.2kg and radius 0.230m is pivoted at its center about

Question

A uniform disk with mass 37.2kg and radius 0.230m is pivoted at its center about a horizontal, frictionless axle that is stationary. The disk is initially at rest, and then a constant force 25.0N is applied tangent to the rim of the disk.

Part A

What is the magnitude v of the tangential velocity of a point on the rim of the disk after the disk has turned through 0.350 revolution?

Part B

What is the magnitude a of the resultant acceleration of a point on the rim of the disk after the disk has turned through 0.350 revolution?

Explanation / Answer

Torque ? = F*r = 25*0.23= 5.7 Nm
Torque ? = I ?, ? is the angular acceleration
I for disc about the given axis = mr

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