An adventurous archaeologist crosses between two rock cliffs by slowly going han

Question

An adventurous archaeologist crosses between two rock cliffs by slowly going hand-over-hand along a rope stretched between the cliffs. He stops to rest at the middle of the rope(Figure 1) . The rope will break if the tension in it exceeds 2.70

An adventurous archaeologist crosses between two rock cliffs by slowly going hand-over-hand along a rope stretched between the cliffs. He stops to rest at the middle of the rope(Figure 1) . The rope will break if the tension in it exceeds 2.70A?104N , and our hero's mass is 94.6kg . 1-If the angle between the rope and the horizontal is 11.6 Degree, find the tension in the rope. 2-What is the smallest value the angle ? can have if the rope is not to break?

Explanation / Answer

1.

The tension in the rope is,

               T = mg / 2sin(theta)

                  = (94.6 kg)(9.8 m/s2)/2sin11.6o

                  = 2305.3 N

---------------------------------------------------------------------------------------

2.

The required smallest angle is,

          theta = sin-1 (mg/2T)

                  = sin-1 [(94.6 kg)(9.8 m/s2) / (2)(2.70104 N)]

               = 0.98o

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.