An adventurous archaeologist crosses between two rock cliffs by slowly going han

Question

An adventurous archaeologist crosses between two rock cliffs by slowly going hand-over-hand along a rope stretched between the cliffs. He stops to rest at the middle of the rope . The rope will break if the tension in it exceeds 2.15×104 , and our hero's mass is 88.9 .
(a)If the angle between the rope and the horizontal is = 10.6, find the tension in the rope. Take the free fall acceleration to be = 9.80.
(b)What is the smallest value the angle can have if the rope is not to break?
Take the free fall acceleration to be = 9.80.

Explanation / Answer

a) T=F of gravity x cos(theta), Plug and chug, and then you should find force of tension. b) set Tension = max tension and then solve for theta

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