A ball is projected horizontally from a table with a height of 1.5 meters and la

Question

A ball is projected horizontally from a table with a height of 1.5 meters and lands 70 cm away from the base of the table. The ball has an initial speed of?
I am getting stuck, I used t= sqrt 2(1.5)/9.8 = .55s for time but I can't figure out where to go from here.
Explanations would be extremely helpful. A ball is projected horizontally from a table with a height of 1.5 meters and lands 70 cm away from the base of the table. The ball has an initial speed of?
I am getting stuck, I used t= sqrt 2(1.5)/9.8 = .55s for time but I can't figure out where to go from here.
Explanations would be extremely helpful.
I am getting stuck, I used t= sqrt 2(1.5)/9.8 = .55s for time but I can't figure out where to go from here.
Explanations would be extremely helpful.

Explanation / Answer

You have horizontal distance covered = 70 cm=0.7m

And thus horizontal velocity = Horizontal distance / Time of fall

= 0.7/ Whatever time you got from the relation

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