A black wood stove with surface area 4.6 m^2 is made from cast iron 4.0 mm thick

Question

A black wood stove with surface area 4.6 m^2 is made from cast iron 4.0 mm thick. The interior wall of the stove is at 650 ?C, while the exterior is at 647 ?C.

Part A

What is the rate of heat conduction through the stove wall?

280

Part B

What is the rate of heat loss by radiation from the stove?

190

Part C

Use the results of parts A and B to find how much heat the stove loses by a combination of conduction and convection in the surrounding air.

Express your answer using two significant figures.

280

Explanation / Answer

Rate of heat conduction = -KA(T2-T1)/l
Given,
A = 4.6 m^2
T2 = 647 degrees
T1 = 650 degrees
l = 4mm = 0.004 m
looking up from the web, for cast iron

K = 55 W/mK

put all values, to get rate of heat transfer = 189.75 KW


now take ambient temperature(T2) to be 25 degrees or 298 K
wall temperature (T1) is 647 degrees or 922K

radiation heat transfer = sA(9224 - 2984)

where A = 4.6m^2

s = 5.668e-8 W/m2K4

put values,

radiation heat transfer = 186.44 KW

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