Two closely spaced wavelengths of light are incident on a diffraction grating. S
ID: 1306990 • Letter: T
Question
Two closely spaced wavelengths of light are incident on a diffraction grating. Starting with the equation below, show that the angular dispersion of the grating is given by the following expression. (Do this on paper. Your instructor may ask you to turn in this work.) d theta /dlambda = m/d cos theta d sin theta bright = m lambda A square grating 1.60 cm on each side containing 7500 equally spaced slits is used to analyze the spectrum of mercury. Two closely spaced lines emitted by this element have wavelengths of 579.065 nm and 576.959 nm. What is the angular separation of these two wavelengths in the second-order spectrum?Explanation / Answer
d theta= (579.959-579.065)*10^-9*2/(468750)
=2.18*10^-13 degrees
Related Questions
Hire Me For All Your Tutoring Needs
Integrity-first tutoring: clear explanations, guidance, and feedback.
Drop an Email at
drjack9650@gmail.com
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.