Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

Any Help would be great!! Thanks! 1.) An electron enters a region of magnetic fi

ID: 1311130 • Letter: A

Question

Any Help would be great!! Thanks!

1.) An electron enters a region of magnetic field of magnitude 0.014 T, traveling perpendicular to the linear boundary of the region. The direction of the field is perpendicular to the velocity of the electron.

(a) Determine the time it takes for the electron to leave the "field-filled" region, noting that its path is a semicircle.
ns

(b) Find the kinetic energy of the electron if the radius of its semicircular path is 2.00 cm.
keV

2.) A particle passes through a mass spectrometer as illustrated in the figure below. The electric field between the plates of the velocity selector has a magnitude of 7934 V/m, and the magnetic fields in both the velocity selector and the deflection chamber have magnitudes of 0.0913 T. In the deflection chamber the particle strikes a photographic plate 39.8 cm removed from its exit point after traveling in a semicircle.

(a) What is the mass-to-charge ratio of the particle?
2.091e-7 kg/C

(b) What is the mass of the particle if it is doubly ionized?
6.69e--26kg

(c) What is its identity, assuming it's an element?

Explanation / Answer

1) Because the path is a semi circle v = ? . r / t

so t ( time in the field ) = ? . r / v

but

m . v^2 / r ( centripetal force ) is supplied by B .e . v ( the magnetic force on the moving charge )

giving v = B . e . r / m

t = ? . m / B . e

Isn't that amazing - the time of flight of the electron depends only on the field strength and not at all on its original velocity.

t = ? * 9.1 10^

Hire Me For All Your Tutoring Needs
Integrity-first tutoring: clear explanations, guidance, and feedback.
Drop an Email at
drjack9650@gmail.com
Chat Now And Get Quote