A large weather balloon whose mass is 220 kg is filled with helium gas until its

Question

A large weather balloon whose mass is 220 kg is filled with helium gas until its volume is 329 m3. Assume the density of air is 1.20 kg/m3 and the density of helium is 0.179 kg/m3.

(a) Calculate the buoyant force acting on the balloon.
? N

(b) Find the net force on the balloon and determine whether the balloon will rise or fall after it is released.

Fnet = ? N

(c) What additional mass can the balloon support in equilibrium?
? kg

Fnet = ? N

(c) What additional mass can the balloon support in equilibrium?
? kg

Explanation / Answer

a) F(b)= pVg (bouyant force is exerted by air)

F(b)= 1.20 * 329 * 9.8

F(b)= 3869.04 N or 3.869 kN

b) F=ma

F(bou) - F(balloon)- F(He) = m(total) * a

3869.04 N - 220*9.8 - .179*329*9.8= ((.179*329)+220)*a

3869.04N - 2156 N - 577.1318 N = 278.891 * a
a= 4.07294 m/s^2 (it will rise)

c)3869.04 -2156 -577.1318 = 1135.9082 N

F=ma

1135.9082=m(9.8)

m= 115.909 kg

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