An average person can reach a maximum height of about 60 cm when jumping straigh

Question

An average person can reach a maximum height of about 60 cm when jumping straight up from a crouched position. During the jump itself, the person's body from the knees up typically rises a distance of around 50 cm. To keep the calculations simple and yet get a reasonable result, assume that the entire body rises this much during the jump.

I need to answer this:

A) With what initial speed does the person leave the ground to reach a height of 60 cm?

and

b)In terms of this jumper's weight W , what force does the ground exert on him or her during the jump?

I know the answer to A is 3.43, but how do you do b and whats the answer?

Explanation / Answer

A) use the formula

V2 = 2gh

that gives

V = 3.43 m/s

b) W = mg

during the jump , the displacement of the body is d =0.5m

so the acceleration a = (V2-Vo2)/2d = 11.76 m/s2

net force applied by ground = m(g+a) = W/g(g+a) = 2.2 W

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