A block with a mass M1=9.9kg rests on the surface of a horizontal table which ha

Question

A block with a mass M1=9.9kg rests on the surface of a horizontal table which has a coefficient of kinetic friction of u_k=0.61. A second block with a mass of M2=11.2kg is connected to the first by an ideal pulley system such that the second block is hanging vertically. The second block is released and motion occurs.

a) Using the variable T to represent tension, write an expression for the sum of the forces in the y direction for block 2.

b) Using the variable T to represent tension, write an expression for the sum of the forces in the x direction for block 1.

Explanation / Answer

Here , taking upwards as positive direction

a) For Block 2 , in y forces

Fy = T - M2*g

b)

Here , for block 1

Fnet = T - u_k * M1*g

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