The 1930kg cable car shown in the figure descends a 200-m-high hill. In addition
ID: 1318328 • Letter: T
Question
The 1930kg cable car shown in the figure descends a 200-m-high hill. In addition to its brakes, the cable car controls its speed by pulling an 1710kg counterweight up the other side of the hill. The rolling friction of both the cable car and the counterweight are negligible. A. How much braking force does the cable car need to descend at constant speed? B. One day the brakes fail just as the cable car leaves the top on its downward journey. What is the runaway car's speed at the bottom of the hill?
Explanation / Answer
Since is moving at a constant speed acceleration is zero
. I found the tension equal to the y component of the weight of the cable car (i have the y component being parallel to the ramp).
1930(9.80)sin30 = 9457N I thought this would be the tension but it's not so i considered the tension in the counterweight as well. 1710(9.8)sin(20) =5731.57 N
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