When a thin 16.0cm iron rod moves with a constant velocity of 5.00m/s perpendicu

Question

When a thin 16.0cm iron rod moves with a constant velocity of 5.00m/s perpendicular to the rod in the direction shown in the figure (Figure 1) , the induced emf across its ends is measured to be 0.500V .

(A) What is the magnitude of the magnetic field? (T)

(B) Which point is at a higher potential, a or b?

(C) If the bar is rotated clockwise by 90.0? in the plane of the paper, but keeps the same velocity, what is the potential difference induced across its ends? (V)

When a thin 16.0cm iron rod moves with a constant velocity of 5.00m/s perpendicular to the rod in the direction shown in the figure (Figure 1) , the induced emf across its ends is measured to be 0.500V . (A) What is the magnitude of the magnetic field? (T) (B) Which point is at a higher potential, a or b? (C) If the bar is rotated clockwise by 90.0? in the plane of the paper, but keeps the same velocity, what is the potential difference induced across its ends? (V)

Explanation / Answer

A) Apply, induced emf = B*v*L*sin(90)

B   = emf/(v*L)

= 0.5/(5*0.16)

= 0.625 T

B) b

C)

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