(a) What power will the bulb dissipate if a total of 26.3 A passes through the w

Question

(a) What power will the bulb dissipate if a total of 26.3 A passes through the wires when the motor comes on? Assume negligible change in bulb resistance.

_______________ W

(b) What power is consumed by the motor?
_________ kW

In the figure below, the voltage source is 120 V, the wire resistance is 0.400 (a) What power will the bulb dissipate if a total of 26.3 A passes through the wires when the motor comes on? Assume negligible change in bulb resistance. _______________ W (b) What power is consumed by the motor? _________ kW Omega, and the bulb is nominally 48.8 W. When the motor (which has a low resistance) comes on, a large current flows causing a significant voltage drop in the wire. This reduces the voltage received by the bulb and causes it to dim noticeably.

Explanation / Answer

part A:

power P = Vi

P = 26.3 * 120

P = 3156 Watts
---------------------------------
part B :

power P = Vi

P = 26.3 * 120

P = 3156 Watts

P of motor = 3156 -40   = 3.146 kWatts

Related Questions

Navigate

• Browse (All)
• Browse #
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.