(a) What potential difference is developed between the airplane\'s wingtips? mV

Question

(a) What potential difference is developed between the airplane's wingtips?
mV

(b) Which wingtip is at higher potential?

The wingtip on the pilot's left.The wingtip on the pilot's right.     

(c) How would the answers to parts (a) and (b) change if the plane turned to fly due east?

Part (a) would increase and part (b) would reverse.Part (a) would increase and part (b) would not change.     Part (a) would decrease and part (b) would reverse.Part (a) would decrease and part (b) would not change.Neither part would change.

(d) Can this emf be used to power a lightbulb in the passenger compartment?

YesNo     

Explain your answer.

A small airplane with a wingspan of 15.5 m is flying due north at a speed of 63.6 m/s over a region where the vertical component of the Earth's magnetic field is 1.20 downward (a) What potential difference is developed between the airplane's wingtips? mV (b) Which wingtip is at higher potential? O The wingtip on the pilot's left. O The wingtip on the pilot's right. (c) How would the answers to parts (a) and (b) change if the plane turned to fly due east? Part (a) would increase and part (b) would reverse O Part (a) would increase and part (b) would not change. O Part (a) would decrease and part (b) would reverse. O Part (a) would decrease and part (b) would not change. O N Neither part would change. (d) Can this emf be used to power a lightbulb in the passenger compartment? O Yes O No Explain your answer.

Explanation / Answer

a) induced emf = B*l*v = 1.2*10^-6*63.6*15.5 = 1.2*10^-3 v

b) the wing tip on the pilot right end

c) Neither part would change

d) No

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