The circuit shown in the diagram at the right contains a battery and 3 resistors

Question

The circuit shown in the diagram at the right contains a battery and 3 resistors. The battery has an EMF of 5 V, R1=2 ohms, R2=3 ohms, and R3=5 ohms. Below are shown 3 graphs tracking some quantity around the curcuit. On the first, plot the volatge a test charge would experience as it moved throughout the circuit. On the second, plot the electric field a test charge would experience as it moved through the circuit. On the third, plot the current one would measure crossing a plane perpendicular to the wire of the circuit as one goes through the circuit. Tracking round a circuit The circuit shown in the diagram at the right contains a battery and 3 resistors. The battery has an EMF of 5 V, R1=2 ohms, R2=3 ohms, and R3=5 ohms. Below are shown 3 graphs tracking some quantity around the curcuit. On the first, plot the volatge a test charge would experience as it moved throughout the circuit. On the second, plot the electric field a test charge would experience as it moved through the circuit. On the third, plot the current one would measure crossing a plane perpendicular to the wire of the circuit as one goes through the circuit.

Explanation / Answer

eq resitance = 2 + 3 + 5 = 10 ohm

V = 5 V

current = 5/10 = 0.5 A

as all resitors are in series thus the current will be the same throught the circuit.

for voltage

before resitor 1 = 5V

after resitor 1 = 5 - 0.5 x 2 = 4 V

before 2nd resitor = 4 V

after resitor 2 = 4 - .5 x 3 = 2.5 V

before 3rd resistor = 2.5 V

after 3rd resistor = 2.5 - .5 x 5 = 0 V

electric field = V/d

now use distance from the restor as required to get the value of Electric field

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