A golf ball is hit off a tee at the edge of a cliff. Its x and y coordinates as

Question

A golf ball is hit off a tee at the edge of a cliff. Its x and y coordinates as functions of time are given by x = 16.9t and y = 4.04t - 4.90t^2, where x and y are in meters and t is in seconds. (a) Write a vector expression for the ball?s position as a function of time, using the unit vectors i and j. (Give the answer in terms of t.) By taking derivatives, do the following. (Give the answers in terms of t.) (b) obtain the expression for the velocity vector v as a function of time (C) obtain the expression for the acceleration vector as a function of time (d) Next use unit-vector notation to write expressions for the position, the velocity, and the acceleration of the golf ball at t = 3.03 s.

Explanation / Answer

a) 17.5t i + (3.96t -5.33t^2)j b) v=dr/dt = 17.5 i +(3.96-10.66t)j c) a=dv/dt = -10.66 j d) [17.5t i + (3.96t -5.33t^2)j]/18.71 [17.5 i +(3.96-10.66t)j]/20.87 -10.66 j /10.66 = -j

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