A point charge +q is at the origin. A spherical Gaussian surface centered at the

Question

A point charge +q is at the origin. A spherical Gaussian surface centered at the origin encloses +q. So does a cubical surface centered at the origin and with edges parallel to the axes. Select "True" or "False" for each statement below. The area vector and the E-Field vector point in the same direction for all points on the cubical surface. A: True B: False If the radius of the spherical Gaussian Surface is varied, the flux through it also varies. A: True: BFalse Suppose (for this statement only), that q is moved from the origin but is still within both the surfaces. The flux through both surfaces is changed A: True B: False By symmetry, the E-Field at all points on the cubical surface is zero. A : True B : False The Electric Flux through the spherical surface is greater than that through the cubical surface A : True B : False Tries 1/4 t 47.1K/S

Explanation / Answer

The reason for all of the anwsers is due to Gauss Law , which states that - The total of the electric flux out of a closed surface is equal to the charge enclosed divided by the permittivity.

1.) False. They point in different direction.
2.) False. It does not depend on radius.
3.) False. Flux depends on charge inside, and as the charge is same, therefore flux is same.
4.) False. It is not Zero.
5.) False. Reason - Charge is same , Therefore Flux is same.

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