A point charge +q is at the origin. A spherical Gaussian surface centred at the

Question

A point charge +q is at the origin. A spherical Gaussian surface centred at the origin encloses +q. So does a cubical surface centered at the origin and with edges parallel to the axes. Select T-True, F-False, If the first is T and the rest F, enter TFFFF.  

A) If the radius of the spherical Gaussian Surface is varied, the flux through it also varies.
B) The area vector and the E-Field vector point in the same direction for all points on the cubical surface.
C) The magnitude of the E-Field at all points on the spherical surface is equal due to spherical symmetry.
D) The Electric Flux through the spherical surface is lesser than that through the cubical surface.
E) Now q is moved from the origin but is sill within both the surfaces. The total flux through both surfaces remains unchanged.

Explanation / Answer

A)

False ,

as according to the gauss law ,

flux through a gaussian surface = charge enclosed/epsilon

B)

False ,

the area is vector point perpendicular to cube surface

while electric field is radially outwards

C)

True ,

as field = K*Q/r^2

the field is same in magnitude at all the points

D)

False

according to the gauss law ,

flux through a gaussian surface = charge enclosed/epsilon

E)

True ,

according to the gauss law ,

flux through a gaussian surface = charge enclosed/epsilon

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