A 46 kg man stands on a bathroom scale in an elevator. Starting from rest, the e

Question

A 46 kg man stands on a bathroom scale in an elevator. Starting from rest, the elevator ascends, attaining its maximum speed of 1.85 m/s in 1.19 s. It travels with this constant speed in the upward direction for the next 7.60 s. The elevator then slows down (undergoes a uniform acceleration in the negative y direction) for 2.15 s and comes to rest.

a)What is the acceleration of the man while the elevator is slowing down on its way upwards? Answer in units of m/s2 and use the upward direction as positive.

b) What does the bathroom scale register during the time the elevator is slowing down on its way upwards? Answer in units of N.

Explanation / Answer

(a) acceleration = v / t = -1.85 / 2.15 = - 0.86 m/s^2

(b) net accelration = g - 0.86 = 9.81 - 0.86 = 8,95 m/s^2

Weight registered on bathroom scale = 46 * 8.95 = 411.7 N

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