A 90-g aluminum calorimeter contains 390 g of water at a temperature of 20C. The

Question

A 90-g aluminum calorimeter contains 390 g of water at a temperature of 20C. Then a 160 g piece of metal, initially at 305C is added to the calorimeter. The metal, water, and calorimeter reach an equilibrium temperature of 32 C. What is the specific heat capacity of the metal? The specific heat capacity of aluminum is 910 J/kg K, and of water is 4190J/kg*K.

310 J/kg · K

350 J/kg · K

430 J/kg · K

470 J/kg · K

A 90-g aluminum calorimeter contains 390 g of water at a temperature of 20C. Then a 160 g piece of metal, initially at 305C is added to the calorimeter. The metal, water, and calorimeter reach an equilibrium temperature of 32 C. What is the specific heat capacity of the metal? The specific heat capacity of aluminum is 910 J/kg K, and of water is 4190J/kg*K.

310 J/kg · K

350 J/kg · K

430 J/kg · K

470 J/kg · K

Explanation / Answer

Here ,

let the specific heat of metal is Sm

heat lost by metal = heat gain by alu + heat gain by water

Sw * 0.160 * (305 - 32) = 0.090 *(32 - 20) * 910 + 0.390 * (32 - 20) * 4186

solving for Sw

Sw = 470 J/kg*K

the specific heat of metal is 470 J/kg*K

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