The 1930 kg cable car shown in the figure descends a 200-m-high hill. In additio

Question

The 1930 kg cable car shown in the figure descends a 200-m-high hill. In addition to its brakes, the cable car controls its speed by pulling an 1810 kg counterweight up the other side of the hill. The rolling friction of both the cable car and the counterweight are negligible.

A) How much braking force does the cable car need to descend at constant speed?

0 0 E https session. masteringphysics.com/r yct/item - ew?assignment roblem D=54475972&offset-prev; MasteringPhysics Assignm https://digital.starbucks.com/?vh=32ddac8f56 Reader Assignments MasteringPhysics: Assignment 15 Click to close this tab; Option-click to close all tabs except this one Figure 1- of 1 Counterweight 200 m 30° 1300 200

Explanation / Answer

Here ,

A)

for the cable car to descend at the constant speed

for the net force to be zero

1930 * sin(30) * 9.8 - Fb - 1810 * sin(20) * 9.8 = 0

solving for Fb

Fb = 3390 N

the braking force required is 3390 N

B)

acceleration of the car is a

a = (1930 * sin(30) * 9.8 - 1810 * sin(20) * 9.8)/(1930 + 1810)

a = 0.91 m/s^2

Now , let the speed at ground is v

v^2 = 2 * 0.91 * (200/sin(30))

v =27 m/s

the velocity of car at the bottom is 27 m/s

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