A spherical object falling under the pull of gravity is acted upon by a friction
ID: 1334934 • Letter: A
Question
A spherical object falling under the pull of gravity is acted upon by a frictional force of air resistance. Assume that the object’s mass is 5.00 kg with a surface area of .140 m^2.
A. What is the terminal speed the object reaches while falling?
B. Does your answer to part (a) depend on the initial speed of the object? Does the initial speed affect how the object approaches its terminal speed? Explain why.
C. Produce a graph of acceleration vs. velocity for the object from the time that the object falls until it reaches its terminal velocity. (I don't understand how to do graphs, please explain)
Explanation / Answer
a. F=mg = bv
b= mg/v
= 5 kg *9.8m/sec^2/ 0.14
= 350 m/sec
PS: This is what your book wants. In actuality F = C* v^2 where C is a constant of drag.
b. No. The object will increase in speed until it reaches terminal velocity.
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