block A has a mass of 2.0kg and is moving at a speed of 6.0m/s towards block B,
ID: 1342748 • Letter: B
Question
block A has a mass of 2.0kg and is moving at a speed of 6.0m/s towards block B, which has a mass of 1.0kg & is placed at rest. if both blocks end up moving together at the same speed, what is the velocity that they both obtain at a conservational lingual momentum. block A has a mass of 2.0kg and is moving at a speed of 6.0m/s towards block B, which has a mass of 1.0kg & is placed at rest. if both blocks end up moving together at the same speed, what is the velocity that they both obtain at a conservational lingual momentum. block A has a mass of 2.0kg and is moving at a speed of 6.0m/s towards block B, which has a mass of 1.0kg & is placed at rest. if both blocks end up moving together at the same speed, what is the velocity that they both obtain at a conservational lingual momentum.Explanation / Answer
From the law of conservation of momentum, we have
m1u1 + m2u2 = (m1 + m2)v
m1u1 + m2(0) = (m1 + m2)v
Hence, the combined speed of the blocks after collision is,
v = m1u1 / m1 + m2 = 2*6 / 2 + 1 = 4 m/s
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