block 1 has mass m1 = 440 g, block 2 has mass m2 = 510 g, and the pulley is on a

Question

block 1 has mass m1 = 440 g, block 2 has mass m2 = 510 g, and the pulley is on a frictionless horizontal axle and has radius R = 4.7 cm. When released from rest, block 2 falls 70 cm in 5.3 s (without the cord slipping on the pulley). What is the pulley's rotational inertia? Caution: Try to avoid rounding off answers along the way to the solution. Use g = 9.81 m/s2. -For some reason I can't put a picture on here but it is a single pully in the center and m1 is hanging down on the left side and m2 is hanging down on the right side

Explanation / Answer

acceleration=v^2/(2*s)
v=0.7/5.3=0.132 m/s
s=0.7 m
a=0.132^2/(2*0.7)=0.0124 m/s^2

m2g-T=m2a

T=0.51*(9.81-0.0124)=5N

T*r=I

=a/r

I=T*r^2/a=5*0.047^2/0.0124=0.89 kg m^2

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