A skier is being towed along a horizontal surface. She has lost her balance and

Question

A skier is being towed along a horizontal surface. She has lost her balance and fallen. however, she maintains her grip on the tow bar. the tow line makes an angle of 15 degrees with the horizontal. she is moving at a constant velocity. the tension in the towrope is 150N. the coefficient of kinetic friction is .200. Find her weight. A skier is being towed along a horizontal surface. She has lost her balance and fallen. however, she maintains her grip on the tow bar. the tow line makes an angle of 15 degrees with the horizontal. she is moving at a constant velocity. the tension in the towrope is 150N. the coefficient of kinetic friction is .200. Find her weight. A skier is being towed along a horizontal surface. She has lost her balance and fallen. however, she maintains her grip on the tow bar. the tow line makes an angle of 15 degrees with the horizontal. she is moving at a constant velocity. the tension in the towrope is 150N. the coefficient of kinetic friction is .200. Find her weight.

Explanation / Answer

here,

angle with horizontal , theta = 15 degree

the tension in the tring , T = 150 N

the coefficient of friction , uk = 0.2

let her weight be w an the normal reaction be N

equating the forces vertically

w - T * sin(15) = N

w - 150 * sin(15) = N ....(1)

equating the forces horizontally

T*sin(theta) - u*N = 0

150 * cos(15) - 0.2 * ( w - 150 * sin(15)) = 0

w = 763.27 N

the weight of the skier is 763.27 N

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