The spin cycles of a washing machine have two angular speeds, 416 rev/min and 64

ID: 1344799 • Letter: T

Question

The spin cycles of a washing machine have two angular speeds, 416 rev/min and 645 rev/min . The internal diameter of the drum is 0.400 m .

A. What is the ratio of the maximum radial force on the laundry for the higher angular speed to that for the lower speed? (f higher/ f lower = )

B. What is the ratio of the maximum tangential speed of the laundry for the higher angular speed to that for the lower speed? (v higher/ v lower = )

C. Find the laundry's maximum tangential speed .

D. Find the laundry's maximum radial acceleration, in terms of g .

Given,

wlower = 416rev/min = (416*2*3.14rad)/60s = 43.54rad/s

whigher = 645rev/min = (645*2*3.14rad)/60s = 67.51rad/s

r= 0.4m

A) Fhigher/Flower = [(mwhigher2/r)/( mwlower2/r)] =whigher2/wlower2 = [(67.51)/( 43.54)]^2= 2.4

B) Vhigher/Vlower = [(whigher *r)/(wlower *r)] = whigher /wlower = (67.51rad/s)/( 43.54rad/s) = 1.55

C) Vhigher = whigher *r = (67.51rad/s)*0.4m = 27.0m/s

D) ac higher = whigher2/r = (67.51)^2/0.4 = 11394 m/s2 = (11394 m/s2/9.8m/s2) = 1162.7g

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