Two children hang by their hands from the same tree branch. The branch is straig

Question

Two children hang by their hands from the same tree branch. The branch is straight, and grows out from the tree trunk at an angle of 27.0° above the horizontal. One child, with a mass of 42.0 kg, is hanging 1.30 m along the branch from the tree trunk. The other child, with a mass of35.0 kg, is hanging 2.45 m from the tree trunk. What is the magnitude of the net torque exerted on the branch by the children? Assume that the axis is located where the branch joins the tree trunk and is perpendicular to the plane formed by the branch and the trunk.

Explanation / Answer

We know that the torque = force*perpendicualr distance
Perpendicular distance of first child of mass (42 kg) = 1.3Cos27 = 1.158 m
Perpendicular distance of second child of mass (35 kg )= 2.45Cos27 = 2.182 m

force due to child of mass 42 kg = 42*9,81 = 412.02 N
force due to chid of mass 35 kg = 35*9.81 = 343.35 N
Torque = 412.02 *1.158 + 343.35*2.182 = 1226.30 Nm

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