A 2.256 -Kg cars is moving down a road with a slope (grade) of 14% at a constant

Question

A 2.256 -Kg cars is moving down a road with a slope (grade) of 14% at a constant speed of 19 m/s. What is the direction and magnitude of the frictional force? (define positive in the forward direction, i.e., down the slope)? A 2,319 - kg car is moving down a road with a slope (grade) of 11% while slowing down at a rate of 3.8 m/s^2. What is the direction and magnitude of the frictional force? (define positive in the forward direction, i,e., down the slope)? A 2.009 -kg car is moving down a road with a slope (grade)of 27% while speeding up at a rate of 1.9 m/s^2. What is the direction and magnitude of the frictional force? (defined positive in the forward direction, i,e., down the slope)? A 1,892 - kg car is moving down a road with a slope (grade) of 12% while speeding up at a rate of 3.7 m/s^2. What is the direction and magnitude of the frictional force? (defined positive in the forward direction, i,e., down the slope)? A2.047 -kg car is moving up a road with a slope (grade) of 35% at a constant speed of 18 m/s. What is the direction and magnitude of the frictional force? A 1,310-kg car is moving up a road with a slope (grade) of 24% while slowing down at a rate of 2.2 m/s^2. What is the direction and magnitude of the frictional force? A 2.180-kg car is moving up a road with a slope (grade) of 13% while slowing down at a rate of 3.9 m/s^2. What is the direction and magnitude of the frictional force

Explanation / Answer

Question 1

frictional force is in upward direction

frictional force = 2,256*9.81*sin(14) = 21473.96 N

Question 2

(m*g*sin(11)) - f = -m*a

(2319*9.81*sin(11))-f = -2319*3.8

f = 13152.98 N in the upward direction

Question 3:

m*g*sin(11)-f = m*a

f = (2009*9.81*sin(27))-(2009*1.9)

f = 5130.3 N in upward direction

Question 4)

f =(1892*9.81*sin(12)) - (1892*3.7) = -3141.45 N upward direction

Question 5)

f = (2047*9.81*sin(35)) = 11518.02 N in downeard direction

Question 6)
f = -(1310*9.81)-(1310*9.81*sin(24)) = -18078.12 downward direction

Question 7) f = (2180*9.81)-(2180*9.81*sin(13)) = 16575N in upward direction

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