1) State and briefly explain Hooke?s Law. What is the elastic potential energy o
ID: 1371776 • Letter: 1
Question
1) State and briefly explain Hooke?s Law. What is the elastic potential energy of a system if obeying Hooke's law? 2)In part 2 of the experiment, Conservation of mechanical energy (K1 + U1 = K2 + U2) is applied (small effects due to friction are ignored). Describe the initial and final states of the system (velocity of the cart, stretched length of the spring relative to the unstretched equilibrium position) by listing the initial and final kinetic and potential energies, K1, U1, K2, and U2 in terms of v=initial velocity of the cart, v2 = final velocity of the cart, X1 = initial position of the cart, X2 = final position of the cart, m = mass of the cart and k = spring constant.Explanation / Answer
Hooke's law is a principle of physics that states that the force F needed to extend or compress a spring by some distance x is proportional to that distance. That is: F=-kx where k is a constant factor characteristic of the spring, its stiffness.
Elastic potential energy: ½*k*x2
At final state initial elastic potential energy is converted into kinetic energy
hence
1/2kx^2=1/2mv^2
v=sqrt(k/m)*x
Cart’s velocity
Spring Length
K
U
Initial State (1)
v=0
X
1/2mv^2= 0
1/2kx^2
Final State (2)
v=sqrt(k/m)*x
0
1/2mv^2=1/2kx^2
1/2kx^2=0
Cart’s velocity
Spring Length
K
U
Initial State (1)
v=0
X
1/2mv^2= 0
1/2kx^2
Final State (2)
v=sqrt(k/m)*x
0
1/2mv^2=1/2kx^2
1/2kx^2=0
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.