a)If the current in the solenoid is ramped at a constant rate from zero to I s =

Question

a)If the current in the solenoid is ramped at a constant rate from zero to Is= 2.80 A over a time interval of 87.0 ms, what is the magnitude of the emf in the outer coil while the current in the solenoid is changing

b)Now reverse the situation. If the current in the short coil is ramped up steadily from zero to Ic= 3.00 A over a time interval of 23.0 ms, what is the magnitude of the emf in the solenoid while the current in the coil is changing?

a)If the current in the solenoid is ramped at a constant rate from zero to Is= 2.80 A over a time interval of 87.0 ms, what is the magnitude of the emf in the outer coil while the current in the solenoid is changing b)Now reverse the situation. If the current in the short coil is ramped up steadily from zero to Ic= 3.00 A over a time interval of 23.0 ms, what is the magnitude of the emf in the solenoid while the current in the coil is changing?

Explanation / Answer

the time derivative of the magnetic field strength:

dB/dt = mu * N * (dI/dt) / h

Here mu is the permeability of the solenoid core (it's just the vacuum permeability mu_0 if you have an air core), N is the number of loops, (dI/dt) is the time derivative of current (given by your max current divided by the time interval;), and h is the length of the solenoid (from end to end). The magnitude of the EMF is simply equal to this number;

|dB/dt| = |EMF|,

dB/dt = mu * N * (dI/dt) / h

here some data is missing ,you should provide  permeability of the solenoid core,number of turns of soleniod and length of the solenoid to solve...the formula to be used is

dB/dt = mu * N * (dI/dt) / h

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